Base | Representation |
---|---|
bin | 10000110110000… |
… | …01000110010010 |
3 | 100211212210022120 |
4 | 20123001012102 |
5 | 242133100424 |
6 | 22004315110 |
7 | 3334013454 |
oct | 1033010622 |
9 | 324783276 |
10 | 141300114 |
11 | 7283a95a |
12 | 3b3a2a96 |
13 | 23374047 |
14 | 14aa22d4 |
15 | c611a79 |
hex | 86c1192 |
141300114 has 32 divisors (see below), whose sum is σ = 294247680. Its totient is φ = 45194112.
The previous prime is 141300097. The next prime is 141300167. The reversal of 141300114 is 411003141.
It is a junction number, because it is equal to n+sod(n) for n = 141300093 and 141300102.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11847 + ... + 20565.
It is an arithmetic number, because the mean of its divisors is an integer number (9195240).
Almost surely, 2141300114 is an apocalyptic number.
141300114 is an abundant number, since it is smaller than the sum of its proper divisors (152947566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141300114 is a wasteful number, since it uses less digits than its factorization.
141300114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8834.
The product of its (nonzero) digits is 48, while the sum is 15.
The square root of 141300114 is about 11886.9724488618. The cubic root of 141300114 is about 520.8518016505.
Adding to 141300114 its reverse (411003141), we get a palindrome (552303255).
The spelling of 141300114 in words is "one hundred forty-one million, three hundred thousand, one hundred fourteen".
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