Base | Representation |
---|---|
bin | 1100110110011110011100… |
… | …1001011010101101000011 |
3 | 1212000211001202201210101220 |
4 | 3031213213021122231003 |
5 | 3323001243003121430 |
6 | 50015124415330123 |
7 | 2655601126361142 |
oct | 315474711325503 |
9 | 55024052653356 |
10 | 14130025442115 |
11 | 4558567aa1860 |
12 | 17025b0b20943 |
13 | 7b65c0195c8b |
14 | 36bc7b07b759 |
15 | 19784b0da110 |
hex | cd9e725ab43 |
14130025442115 has 96 divisors (see below), whose sum is σ = 26049825732096. Its totient is φ = 6485329912320.
The previous prime is 14130025442089. The next prime is 14130025442149. The reversal of 14130025442115 is 51124452003141.
It is not a de Polignac number, because 14130025442115 - 235 = 14095665703747 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 77522167 + ... + 77704223.
It is an arithmetic number, because the mean of its divisors is an integer number (271352351376).
Almost surely, 214130025442115 is an apocalyptic number.
14130025442115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14130025442115 is a deficient number, since it is larger than the sum of its proper divisors (11919800289981).
14130025442115 is a wasteful number, since it uses less digits than its factorization.
14130025442115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183417 (or 183398 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 14130025442115 its reverse (51124452003141), we get a palindrome (65254477445256).
The spelling of 14130025442115 in words is "fourteen trillion, one hundred thirty billion, twenty-five million, four hundred forty-two thousand, one hundred fifteen".
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