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141300254455 = 5247711408983
BaseRepresentation
bin1000001110011000100…
…1101100011011110111
3111111201110100122112121
42003212021230123313
54303340331120310
6144525030500411
713131360226423
oct2034611543367
9444643318477
10141300254455
1154a1a3455a8
1223475204707
131042b088a29
146ba61b7b83
153a1ee620da
hex20e626c6f7

141300254455 has 8 divisors (see below), whose sum is σ = 169628774112. Its totient is φ = 112994557728.

The previous prime is 141300254449. The next prime is 141300254477. The reversal of 141300254455 is 554452003141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141300254455 - 25 = 141300254423 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 141300254455.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5692107 + ... + 5716876.

It is an arithmetic number, because the mean of its divisors is an integer number (21203596764).

Almost surely, 2141300254455 is an apocalyptic number.

141300254455 is a deficient number, since it is larger than the sum of its proper divisors (28328519657).

141300254455 is a wasteful number, since it uses less digits than its factorization.

141300254455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11411465.

The product of its (nonzero) digits is 48000, while the sum is 34.

Adding to 141300254455 its reverse (554452003141), we get a palindrome (695752257596).

The spelling of 141300254455 in words is "one hundred forty-one billion, three hundred million, two hundred fifty-four thousand, four hundred fifty-five".

Divisors: 1 5 2477 12385 11408983 57044915 28260050891 141300254455