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14130113443 = 44513174593
BaseRepresentation
bin11010010100011100…
…00110101110100011
31100110202022010122221
431022032012232203
5212414302112233
610254041211511
71010104661005
oct151216065643
940422263587
1014130113443
115aa1098406
1228a4190b97
131442567194
149808a6375
1557a78542d
hex34a386ba3

14130113443 has 4 divisors (see below), whose sum is σ = 14133292488. Its totient is φ = 14126934400.

The previous prime is 14130113423. The next prime is 14130113453. The reversal of 14130113443 is 34431103141.

It is a happy number.

14130113443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14130113443 - 213 = 14130105251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14130113423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1582846 + ... + 1591747.

It is an arithmetic number, because the mean of its divisors is an integer number (3533323122).

Almost surely, 214130113443 is an apocalyptic number.

14130113443 is a deficient number, since it is larger than the sum of its proper divisors (3179045).

14130113443 is an equidigital number, since it uses as much as digits as its factorization.

14130113443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3179044.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 14130113443 its reverse (34431103141), we get a palindrome (48561216584).

The spelling of 14130113443 in words is "fourteen billion, one hundred thirty million, one hundred thirteen thousand, four hundred forty-three".

Divisors: 1 4451 3174593 14130113443