1413012052433 has 2 divisors, whose sum is σ = 1413012052434. Its totient is φ = 1413012052432.

The previous prime is 1413012052409. The next prime is 1413012052523. The reversal of 1413012052433 is 3342502103141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1394059574209 + 18952478224 = 1180703^2 + 137668^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413012052433 - 2²⁴ = 1412995275217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1413012052396 and 1413012052405.

It is not a weakly prime, because it can be changed into another prime (1413012057433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706506026216 + 706506026217.

It is an arithmetic number, because the mean of its divisors is an integer number (706506026217).

Almost surely, 2^{1413012052433} is an apocalyptic number.

It is an amenable number.

1413012052433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413012052433 is an equidigital number, since it uses as much as digits as its factorization.

1413012052433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1413012052433 its reverse (3342502103141), we get a palindrome (4755514155574).

The spelling of 1413012052433 in words is "one trillion, four hundred thirteen billion, twelve million, fifty-two thousand, four hundred thirty-three".