1413032000041 has 2 divisors, whose sum is σ = 1413032000042. Its totient is φ = 1413032000040.

The previous prime is 1413031999957. The next prime is 1413032000057. The reversal of 1413032000041 is 1400002303141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1231467381225 + 181564618816 = 1109715^2 + 426104^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413032000041 - 2¹³ = 1413031991849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1413031999982 and 1413032000018.

It is not a weakly prime, because it can be changed into another prime (1413032000741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706516000020 + 706516000021.

It is an arithmetic number, because the mean of its divisors is an integer number (706516000021).

Almost surely, 2^{1413032000041} is an apocalyptic number.

It is an amenable number.

1413032000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413032000041 is an equidigital number, since it uses as much as digits as its factorization.

1413032000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 1413032000041 its reverse (1400002303141), we get a palindrome (2813034303182).

The spelling of 1413032000041 in words is "one trillion, four hundred thirteen billion, thirty-two million, forty-one", and thus it is an aban number.