Base | Representation |
---|---|
bin | 100000001000001110111000… |
… | …111101000111100000111011 |
3 | 200112022110100012100201001222 |
4 | 200020032320331013200323 |
5 | 122010103004404203121 |
6 | 1220305450401502255 |
7 | 41522551550254643 |
oct | 4010167075074073 |
9 | 615273305321058 |
10 | 141303232100411 |
11 | 410294008312a7 |
12 | 13a2161a64198b |
13 | 60acab7305694 |
14 | 26c7181c19523 |
15 | 115094c0510ab |
hex | 8083b8f4783b |
141303232100411 has 2 divisors, whose sum is σ = 141303232100412. Its totient is φ = 141303232100410.
The previous prime is 141303232100351. The next prime is 141303232100449. The reversal of 141303232100411 is 114001232303141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141303232100411 is a prime.
It is a super-3 number, since 3×1413032321004113 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (141303262100411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70651616050205 + 70651616050206.
It is an arithmetic number, because the mean of its divisors is an integer number (70651616050206).
Almost surely, 2141303232100411 is an apocalyptic number.
141303232100411 is a deficient number, since it is larger than the sum of its proper divisors (1).
141303232100411 is an equidigital number, since it uses as much as digits as its factorization.
141303232100411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 141303232100411 its reverse (114001232303141), we get a palindrome (255304464403552).
The spelling of 141303232100411 in words is "one hundred forty-one trillion, three hundred three billion, two hundred thirty-two million, one hundred thousand, four hundred eleven".
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