Base | Representation |
---|---|
bin | 100000001000001110111000… |
… | …111101000111101011101111 |
3 | 200112022110100012100202000121 |
4 | 200020032320331013223233 |
5 | 122010103004404213403 |
6 | 1220305450401505411 |
7 | 41522551550256652 |
oct | 4010167075075357 |
9 | 615273305322017 |
10 | 141303232101103 |
11 | 41029400831876 |
12 | 13a2161a642267 |
13 | 60acab7305aa7 |
14 | 26c7181c19899 |
15 | 115094c0513bd |
hex | 8083b8f47aef |
141303232101103 has 4 divisors (see below), whose sum is σ = 141303481833240. Its totient is φ = 141302982368968.
The previous prime is 141303232101079. The next prime is 141303232101121. The reversal of 141303232101103 is 301101232303141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141303232101103 - 245 = 106118860012271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141303232101193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124015408 + ... + 125149621.
It is an arithmetic number, because the mean of its divisors is an integer number (35325870458310).
Almost surely, 2141303232101103 is an apocalyptic number.
141303232101103 is a deficient number, since it is larger than the sum of its proper divisors (249732137).
141303232101103 is an equidigital number, since it uses as much as digits as its factorization.
141303232101103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 249732136.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 141303232101103 its reverse (301101232303141), we get a palindrome (442404464404244).
The spelling of 141303232101103 in words is "one hundred forty-one trillion, three hundred three billion, two hundred thirty-two million, one hundred one thousand, one hundred three".
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