Base | Representation |
---|---|
bin | 1100110110100000000000… |
… | …1011001110001011111011 |
3 | 1212000212011000212002121021 |
4 | 3031220000023032023323 |
5 | 3323003123002024111 |
6 | 50015234215323311 |
7 | 2655614415450304 |
oct | 315500013161373 |
9 | 55025130762537 |
10 | 14130445345531 |
11 | 4558763021479 |
12 | 17026a9680537 |
13 | 7b6659185a38 |
14 | 36bcbab437ab |
15 | 197872dd0d71 |
hex | cda002ce2fb |
14130445345531 has 2 divisors, whose sum is σ = 14130445345532. Its totient is φ = 14130445345530.
The previous prime is 14130445345463. The next prime is 14130445345547. The reversal of 14130445345531 is 13554354403141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14130445345531 - 27 = 14130445345403 is a prime.
It is a super-2 number, since 2×141304453455312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14130445345931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065222672765 + 7065222672766.
It is an arithmetic number, because the mean of its divisors is an integer number (7065222672766).
Almost surely, 214130445345531 is an apocalyptic number.
14130445345531 is a deficient number, since it is larger than the sum of its proper divisors (1).
14130445345531 is an equidigital number, since it uses as much as digits as its factorization.
14130445345531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 14130445345531 its reverse (13554354403141), we get a palindrome (27684799748672).
The spelling of 14130445345531 in words is "fourteen trillion, one hundred thirty billion, four hundred forty-five million, three hundred forty-five thousand, five hundred thirty-one".
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