14130500533 has 4 divisors (see below), whose sum is σ = 14130953388. Its totient is φ = 14130047680.

The previous prime is 14130500437. The next prime is 14130500537. The reversal of 14130500533 is 33500503141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33500503141 = 7 ⋅4785786163.

It can be written as a sum of positive squares in 2 ways, for example, as 2470388209 + 11660112324 = 49703^2 + 107982^2 .

It is a cyclic number.

It is not a de Polignac number, because 14130500533 - 2²¹ = 14128403381 is a prime.

It is a super-2 number, since 2×14130500533² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14130500498 and 14130500507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14130500537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175858 + ... + 243283.

It is an arithmetic number, because the mean of its divisors is an integer number (3532738347).

Almost surely, 2^14130500533 is an apocalyptic number.

It is an amenable number.

14130500533 is a deficient number, since it is larger than the sum of its proper divisors (452855).

14130500533 is an equidigital number, since it uses as much as digits as its factorization.

14130500533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 452854.

The product of its (nonzero) digits is 2700, while the sum is 25.

The spelling of 14130500533 in words is "fourteen billion, one hundred thirty million, five hundred thousand, five hundred thirty-three".