Base | Representation |
---|---|
bin | 1100110110100000010101… |
… | …0000101011011010011110 |
3 | 1212000212100222101121212012 |
4 | 3031220011100223122132 |
5 | 3323003311322141141 |
6 | 50015250504111222 |
7 | 2655616502565431 |
oct | 315500520533236 |
9 | 55025328347765 |
10 | 14130530662046 |
11 | 45587a71a3a97 |
12 | 1702712165512 |
13 | 7b6670a57c96 |
14 | 36bcc81d1818 |
15 | 19787a634ceb |
hex | cda0542b69e |
14130530662046 has 4 divisors (see below), whose sum is σ = 21195795993072. Its totient is φ = 7065265331022.
The previous prime is 14130530662019. The next prime is 14130530662093. The reversal of 14130530662046 is 64026603503141.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×141305306620462 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14130530661994 and 14130530662012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3532632665510 + ... + 3532632665513.
It is an arithmetic number, because the mean of its divisors is an integer number (5298948998268).
Almost surely, 214130530662046 is an apocalyptic number.
14130530662046 is a deficient number, since it is larger than the sum of its proper divisors (7065265331026).
14130530662046 is an equidigital number, since it uses as much as digits as its factorization.
14130530662046 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7065265331025.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 14130530662046 in words is "fourteen trillion, one hundred thirty billion, five hundred thirty million, six hundred sixty-two thousand, forty-six".
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