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141305450401 is a prime number
BaseRepresentation
bin1000001110011001110…
…1100000111110100001
3111111201211010122001001
42003212131200332201
54303343143403101
6144525334112001
713131452340103
oct2034635407641
9444654118031
10141305450401
1154a22274375
1223476aab601
131042c187a5b
146ba6b6b573
153a2063b901
hex20e6760fa1

141305450401 has 2 divisors, whose sum is σ = 141305450402. Its totient is φ = 141305450400.

The previous prime is 141305450353. The next prime is 141305450453. The reversal of 141305450401 is 104054503141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86892890176 + 54412560225 = 294776^2 + 233265^2 .

It is a cyclic number.

It is not a de Polignac number, because 141305450401 - 211 = 141305448353 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141305450401.

It is not a weakly prime, because it can be changed into another prime (141305450471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70652725200 + 70652725201.

It is an arithmetic number, because the mean of its divisors is an integer number (70652725201).

Almost surely, 2141305450401 is an apocalyptic number.

It is an amenable number.

141305450401 is a deficient number, since it is larger than the sum of its proper divisors (1).

141305450401 is an equidigital number, since it uses as much as digits as its factorization.

141305450401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 141305450401 its reverse (104054503141), we get a palindrome (245359953542).

The spelling of 141305450401 in words is "one hundred forty-one billion, three hundred five million, four hundred fifty thousand, four hundred one".