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141305561539 is a prime number
BaseRepresentation
bin1000001110011001110…
…1111100000111000011
3111111201211100021111021
42003212131330013003
54303343210432124
6144525340330311
713131453312112
oct2034635740703
9444654307437
10141305561539
1154a2233a91a
1223476b43997
131042c1c650c
146ba6b99c79
153a2065e7e4
hex20e677c1c3

141305561539 has 2 divisors, whose sum is σ = 141305561540. Its totient is φ = 141305561538.

The previous prime is 141305561521. The next prime is 141305561543. The reversal of 141305561539 is 935165503141.

141305561539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141305561539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141305561495 and 141305561504.

It is not a weakly prime, because it can be changed into another prime (141305561549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70652780769 + 70652780770.

It is an arithmetic number, because the mean of its divisors is an integer number (70652780770).

Almost surely, 2141305561539 is an apocalyptic number.

141305561539 is a deficient number, since it is larger than the sum of its proper divisors (1).

141305561539 is an equidigital number, since it uses as much as digits as its factorization.

141305561539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 43.

The spelling of 141305561539 in words is "one hundred forty-one billion, three hundred five million, five hundred sixty-one thousand, five hundred thirty-nine".