Base | Representation |
---|---|
bin | 1100110110100010001100… |
… | …0110001100111110010011 |
3 | 1212000220122212022020022001 |
4 | 3031220203012030332103 |
5 | 3323010322443414103 |
6 | 50015412305054431 |
7 | 2655635061426301 |
oct | 315504306147623 |
9 | 55026585266261 |
10 | 14131031232403 |
11 | 4558a3380a9a8 |
12 | 1702831927417 |
13 | 7b672067c867 |
14 | 36bd34895271 |
15 | 1978a956201d |
hex | cda2318cf93 |
14131031232403 has 2 divisors, whose sum is σ = 14131031232404. Its totient is φ = 14131031232402.
The previous prime is 14131031232359. The next prime is 14131031232427. The reversal of 14131031232403 is 30423213013141.
14131031232403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14131031232403 is a prime.
It is a super-2 number, since 2×141310312324032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14131031232103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065515616201 + 7065515616202.
It is an arithmetic number, because the mean of its divisors is an integer number (7065515616202).
Almost surely, 214131031232403 is an apocalyptic number.
14131031232403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14131031232403 is an equidigital number, since it uses as much as digits as its factorization.
14131031232403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 14131031232403 its reverse (30423213013141), we get a palindrome (44554244245544).
The spelling of 14131031232403 in words is "fourteen trillion, one hundred thirty-one billion, thirty-one million, two hundred thirty-two thousand, four hundred three".
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