Base | Representation |
---|---|
bin | 10100100100000100110… |
… | …010001011110110110111 |
3 | 12000002112002001201201012 |
4 | 110210010302023312313 |
5 | 141123034333130030 |
6 | 3001102550222435 |
7 | 204044354051036 |
oct | 24440462136667 |
9 | 5002462051635 |
10 | 1413124505015 |
11 | 4a5336a41153 |
12 | 1a9a58654a1b |
13 | a3345a1c182 |
14 | 4c57770471d |
15 | 26b5a4a7095 |
hex | 14904c8bdb7 |
1413124505015 has 4 divisors (see below), whose sum is σ = 1695749406024. Its totient is φ = 1130499604008.
The previous prime is 1413124504999. The next prime is 1413124505017. The reversal of 1413124505015 is 5105054213141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1413124505015 - 24 = 1413124504999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1413124505017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141312450497 + ... + 141312450506.
It is an arithmetic number, because the mean of its divisors is an integer number (423937351506).
Almost surely, 21413124505015 is an apocalyptic number.
1413124505015 is a deficient number, since it is larger than the sum of its proper divisors (282624901009).
1413124505015 is an equidigital number, since it uses as much as digits as its factorization.
1413124505015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 282624901008.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 1413124505015 its reverse (5105054213141), we get a palindrome (6518178718156).
The spelling of 1413124505015 in words is "one trillion, four hundred thirteen billion, one hundred twenty-four million, five hundred five thousand, fifteen".
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