Base | Representation |
---|---|
bin | 10100100100000111010… |
… | …010110001010000010001 |
3 | 12000002122000021102212101 |
4 | 110210013102301100101 |
5 | 141123131122214413 |
6 | 3001111052400401 |
7 | 204045404626402 |
oct | 24440722612021 |
9 | 5002560242771 |
10 | 1413166601233 |
11 | 4a5358783712 |
12 | 1a9a6a776101 |
13 | a335166ab8a |
14 | 4c57d1419a9 |
15 | 26b5e01eedd |
hex | 149074b1411 |
1413166601233 has 2 divisors, whose sum is σ = 1413166601234. Its totient is φ = 1413166601232.
The previous prime is 1413166601219. The next prime is 1413166601281. The reversal of 1413166601233 is 3321066613141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 901565442064 + 511601159169 = 949508^2 + 715263^2 .
It is a cyclic number.
It is not a de Polignac number, because 1413166601233 - 233 = 1404576666641 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1413166601192 and 1413166601201.
It is not a weakly prime, because it can be changed into another prime (1413166601633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706583300616 + 706583300617.
It is an arithmetic number, because the mean of its divisors is an integer number (706583300617).
Almost surely, 21413166601233 is an apocalyptic number.
It is an amenable number.
1413166601233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413166601233 is an equidigital number, since it uses as much as digits as its factorization.
1413166601233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 37.
The spelling of 1413166601233 in words is "one trillion, four hundred thirteen billion, one hundred sixty-six million, six hundred one thousand, two hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •