Base | Representation |
---|---|
bin | 1000001110011101010… |
… | …1101110011010001011 |
3 | 111111202211212020202211 |
4 | 2003213111232122023 |
5 | 4303410431413413 |
6 | 144531022005551 |
7 | 13132021520401 |
oct | 2034725563213 |
9 | 444684766684 |
10 | 141320185483 |
11 | 54a2a619024 |
12 | 2347ba168b7 |
13 | 10432246939 |
14 | 6ba8ac5471 |
15 | 3a21a9c83d |
hex | 20e756e68b |
141320185483 has 2 divisors, whose sum is σ = 141320185484. Its totient is φ = 141320185482.
The previous prime is 141320185477. The next prime is 141320185507. The reversal of 141320185483 is 384581023141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141320185483 - 213 = 141320177291 is a prime.
It is not a weakly prime, because it can be changed into another prime (141320185403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70660092741 + 70660092742.
It is an arithmetic number, because the mean of its divisors is an integer number (70660092742).
Almost surely, 2141320185483 is an apocalyptic number.
141320185483 is a deficient number, since it is larger than the sum of its proper divisors (1).
141320185483 is an equidigital number, since it uses as much as digits as its factorization.
141320185483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92160, while the sum is 40.
The spelling of 141320185483 in words is "one hundred forty-one billion, three hundred twenty million, one hundred eighty-five thousand, four hundred eighty-three".
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