1413210553 has 4 divisors (see below), whose sum is σ = 1413296640. Its totient is φ = 1413124468.

The previous prime is 1413210499. The next prime is 1413210563. The reversal of 1413210553 is 3550123141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3550123141 = 17 ⋅208830773.

It is a cyclic number.

It is not a de Polignac number, because 1413210553 - 2²¹ = 1411113401 is a prime.

It is a super-2 number, since 2×1413210553² = 3994328134221131618, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413210563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9925 + ... + 54082.

It is an arithmetic number, because the mean of its divisors is an integer number (353324160).

Almost surely, 2^1413210553 is an apocalyptic number.

It is an amenable number.

1413210553 is a deficient number, since it is larger than the sum of its proper divisors (86087).

1413210553 is an equidigital number, since it uses as much as digits as its factorization.

1413210553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86086.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 1413210553 is about 37592.6928138967. The cubic root of 1413210553 is about 1122.1966225274.

Adding to 1413210553 its reverse (3550123141), we get a palindrome (4963333694).

The spelling of 1413210553 in words is "one billion, four hundred thirteen million, two hundred ten thousand, five hundred fifty-three".