Base | Representation |
---|---|
bin | 1100110110100110001110… |
… | …0001001000110110000011 |
3 | 1212001000110012000201000101 |
4 | 3031221203201020312003 |
5 | 3323020031140111303 |
6 | 50020111434303231 |
7 | 2656003624206001 |
oct | 315514341106603 |
9 | 55030405021011 |
10 | 14132112035203 |
11 | 4559438903058 |
12 | 1702a93887b17 |
13 | 7b686356b646 |
14 | 36bdd8237a71 |
15 | 19791e3a4d1d |
hex | cda63848d83 |
14132112035203 has 2 divisors, whose sum is σ = 14132112035204. Its totient is φ = 14132112035202.
The previous prime is 14132112035143. The next prime is 14132112035207. The reversal of 14132112035203 is 30253021123141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14132112035203 is a prime.
It is a super-2 number, since 2×141321120352032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14132112035207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066056017601 + 7066056017602.
It is an arithmetic number, because the mean of its divisors is an integer number (7066056017602).
Almost surely, 214132112035203 is an apocalyptic number.
14132112035203 is a deficient number, since it is larger than the sum of its proper divisors (1).
14132112035203 is an equidigital number, since it uses as much as digits as its factorization.
14132112035203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 14132112035203 its reverse (30253021123141), we get a palindrome (44385133158344).
The spelling of 14132112035203 in words is "fourteen trillion, one hundred thirty-two billion, one hundred twelve million, thirty-five thousand, two hundred three".
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