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14132120011 is a prime number
BaseRepresentation
bin11010010100101011…
…10000100111001011
31100110220002002011021
431022111300213023
5212420310320021
610254152213311
71010131016032
oct151225604713
940426062137
1014132120011
115aa2238a29
1228a499a237
131442aba5b9
14980c69719
1557aa2ec41
hex34a5709cb

14132120011 has 2 divisors, whose sum is σ = 14132120012. Its totient is φ = 14132120010.

The previous prime is 14132119999. The next prime is 14132120021. The reversal of 14132120011 is 11002123141.

14132120011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11002123141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14132120011 - 215 = 14132087243 is a prime.

It is not a weakly prime, because it can be changed into another prime (14132120021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066060005 + 7066060006.

It is an arithmetic number, because the mean of its divisors is an integer number (7066060006).

Almost surely, 214132120011 is an apocalyptic number.

14132120011 is a deficient number, since it is larger than the sum of its proper divisors (1).

14132120011 is an equidigital number, since it uses as much as digits as its factorization.

14132120011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 14132120011 its reverse (11002123141), we get a palindrome (25134243152).

The spelling of 14132120011 in words is "fourteen billion, one hundred thirty-two million, one hundred twenty thousand, eleven".