Base | Representation |
---|---|
bin | 100000001000011111110011… |
… | …111010111000111101011001 |
3 | 200112101012020102210200221221 |
4 | 200020133303322320331121 |
5 | 122010402212204211213 |
6 | 1220322053325332041 |
7 | 41524064031360400 |
oct | 4010376372707531 |
9 | 615335212720857 |
10 | 141321401241433 |
11 | 41036084839926 |
12 | 13a2504b407021 |
13 | 60b17215a72ba |
14 | 26c7dc6cb4637 |
15 | 11511621ba38d |
hex | 8087f3eb8f59 |
141321401241433 has 48 divisors (see below), whose sum is σ = 170655374534400. Its totient is φ = 116600294603520.
The previous prime is 141321401241379. The next prime is 141321401241469. The reversal of 141321401241433 is 334142104123141.
It is not a de Polignac number, because 141321401241433 - 213 = 141321401233241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141321401241473) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 226168603 + ... + 226792591.
It is an arithmetic number, because the mean of its divisors is an integer number (3555320302800).
Almost surely, 2141321401241433 is an apocalyptic number.
It is an amenable number.
141321401241433 is a deficient number, since it is larger than the sum of its proper divisors (29333973292967).
141321401241433 is a wasteful number, since it uses less digits than its factorization.
141321401241433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 625550 (or 625543 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 141321401241433 its reverse (334142104123141), we get a palindrome (475463505364574).
The spelling of 141321401241433 in words is "one hundred forty-one trillion, three hundred twenty-one billion, four hundred one million, two hundred forty-one thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •