Base | Representation |
---|---|
bin | 11010010100101011… |
… | …10110010011100011 |
3 | 1100110220010021010222 |
4 | 31022111312103203 |
5 | 212420312041311 |
6 | 10254152513255 |
7 | 1010131144025 |
oct | 151225662343 |
9 | 40426107128 |
10 | 14132143331 |
11 | 5aa22544a9 |
12 | 28a49ab82b |
13 | 1442ac80b7 |
14 | 980c74015 |
15 | 57aa36adb |
hex | 34a5764e3 |
14132143331 has 2 divisors, whose sum is σ = 14132143332. Its totient is φ = 14132143330.
The previous prime is 14132143309. The next prime is 14132143349. The reversal of 14132143331 is 13334123141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14132143331 is a prime.
It is a super-2 number, since 2×141321433312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14132143331.
It is not a weakly prime, because it can be changed into another prime (14132143301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066071665 + 7066071666.
It is an arithmetic number, because the mean of its divisors is an integer number (7066071666).
Almost surely, 214132143331 is an apocalyptic number.
14132143331 is a deficient number, since it is larger than the sum of its proper divisors (1).
14132143331 is an equidigital number, since it uses as much as digits as its factorization.
14132143331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 26.
Adding to 14132143331 its reverse (13334123141), we get a palindrome (27466266472).
The spelling of 14132143331 in words is "fourteen billion, one hundred thirty-two million, one hundred forty-three thousand, three hundred thirty-one".
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