Base | Representation |
---|---|
bin | 10100100100001010001… |
… | …111011101001111101001 |
3 | 12000002202110100102200211 |
4 | 110210022033131033221 |
5 | 141123231303030424 |
6 | 3001120020501121 |
7 | 204046545230215 |
oct | 24441217351751 |
9 | 5002673312624 |
10 | 1413216064489 |
11 | 4a5383698139 |
12 | 1a9a8324a7a1 |
13 | a335b998b88 |
14 | 4c585939945 |
15 | 26b63540b94 |
hex | 1490a3dd3e9 |
1413216064489 has 2 divisors, whose sum is σ = 1413216064490. Its totient is φ = 1413216064488.
The previous prime is 1413216064457. The next prime is 1413216064577. The reversal of 1413216064489 is 9844606123141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1391373589225 + 21842475264 = 1179565^2 + 147792^2 .
It is a cyclic number.
It is not a de Polignac number, because 1413216064489 - 25 = 1413216064457 is a prime.
It is a super-2 number, since 2×14132160644892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1413216004489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706608032244 + 706608032245.
It is an arithmetic number, because the mean of its divisors is an integer number (706608032245).
Almost surely, 21413216064489 is an apocalyptic number.
It is an amenable number.
1413216064489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413216064489 is an equidigital number, since it uses as much as digits as its factorization.
1413216064489 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 995328, while the sum is 49.
The spelling of 1413216064489 in words is "one trillion, four hundred thirteen billion, two hundred sixteen million, sixty-four thousand, four hundred eighty-nine".
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