Base | Representation |
---|---|
bin | 11010010100101100… |
… | …01001000101011101 |
3 | 1100110220021011122221 |
4 | 31022112021011131 |
5 | 212420322022003 |
6 | 10254154305341 |
7 | 1010131614214 |
oct | 151226110535 |
9 | 40426234587 |
10 | 14132220253 |
11 | 5aa22a7278 |
12 | 28a4a28251 |
13 | 1442b24108 |
14 | 980c9407b |
15 | 57aa4e7bd |
hex | 34a58915d |
14132220253 has 4 divisors (see below), whose sum is σ = 14140148128. Its totient is φ = 14124292380.
The previous prime is 14132220251. The next prime is 14132220301. The reversal of 14132220253 is 35202223141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14132220253 - 21 = 14132220251 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14132220251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3961263 + ... + 3964828.
It is an arithmetic number, because the mean of its divisors is an integer number (3535037032).
Almost surely, 214132220253 is an apocalyptic number.
It is an amenable number.
14132220253 is a deficient number, since it is larger than the sum of its proper divisors (7927875).
14132220253 is an equidigital number, since it uses as much as digits as its factorization.
14132220253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7927874.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 14132220253 its reverse (35202223141), we get a palindrome (49334443394).
The spelling of 14132220253 in words is "fourteen billion, one hundred thirty-two million, two hundred twenty thousand, two hundred fifty-three".
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