Base | Representation |
---|---|
bin | 11010010100101101… |
… | …00100100111010011 |
3 | 1100110220110220100011 |
4 | 31022112210213103 |
5 | 212420334124021 |
6 | 10254200535351 |
7 | 1010132564026 |
oct | 151226444723 |
9 | 40426426304 |
10 | 14132333011 |
11 | 5aa2373a65 |
12 | 28a4a81557 |
13 | 1442b63534 |
14 | 980cc31bd |
15 | 57aa72de1 |
hex | 34a5a49d3 |
14132333011 has 2 divisors, whose sum is σ = 14132333012. Its totient is φ = 14132333010.
The previous prime is 14132332997. The next prime is 14132333023. The reversal of 14132333011 is 11033323141.
14132333011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14132333011 - 217 = 14132201939 is a prime.
It is a super-2 number, since 2×141323330112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14132330011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066166505 + 7066166506.
It is an arithmetic number, because the mean of its divisors is an integer number (7066166506).
Almost surely, 214132333011 is an apocalyptic number.
14132333011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14132333011 is an equidigital number, since it uses as much as digits as its factorization.
14132333011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 14132333011 its reverse (11033323141), we get a palindrome (25165656152).
The spelling of 14132333011 in words is "fourteen billion, one hundred thirty-two million, three hundred thirty-three thousand, eleven".
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