Base | Representation |
---|---|
bin | 1100110110100111011000… |
… | …0101111001011101011011 |
3 | 1212001001020220101221210111 |
4 | 3031221312011321131123 |
5 | 3323021200424131103 |
6 | 50020202405425151 |
7 | 2656014430040125 |
oct | 315516605713533 |
9 | 55031226357714 |
10 | 14132423661403 |
11 | 45595887a8473 |
12 | 1702b6010b1b7 |
13 | 7b68b2caa248 |
14 | 36c027796215 |
15 | 19793b90d86d |
hex | cda7617975b |
14132423661403 has 2 divisors, whose sum is σ = 14132423661404. Its totient is φ = 14132423661402.
The previous prime is 14132423661337. The next prime is 14132423661431. The reversal of 14132423661403 is 30416632423141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14132423661403 - 221 = 14132421564251 is a prime.
It is not a weakly prime, because it can be changed into another prime (14132423662403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066211830701 + 7066211830702.
It is an arithmetic number, because the mean of its divisors is an integer number (7066211830702).
Almost surely, 214132423661403 is an apocalyptic number.
14132423661403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14132423661403 is an equidigital number, since it uses as much as digits as its factorization.
14132423661403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 40.
The spelling of 14132423661403 in words is "fourteen trillion, one hundred thirty-two billion, four hundred twenty-three million, six hundred sixty-one thousand, four hundred three".
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