Base | Representation |
---|---|
bin | 1100110110100111101010… |
… | …1011001011110110110011 |
3 | 1212001001110021002001012011 |
4 | 3031221322223023312303 |
5 | 3323021330114414242 |
6 | 50020214153343351 |
7 | 2656016352403321 |
oct | 315517253136663 |
9 | 55031407061164 |
10 | 14132500544947 |
11 | 4559618140194 |
12 | 1702b81a07b57 |
13 | 7b68c5bb8c75 |
14 | 36c033a8ad11 |
15 | 197943548d17 |
hex | cda7aacbdb3 |
14132500544947 has 2 divisors, whose sum is σ = 14132500544948. Its totient is φ = 14132500544946.
The previous prime is 14132500544933. The next prime is 14132500544957. The reversal of 14132500544947 is 74944500523141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14132500544947 - 223 = 14132492156339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14132500544947.
It is not a weakly prime, because it can be changed into another prime (14132500544957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066250272473 + 7066250272474.
It is an arithmetic number, because the mean of its divisors is an integer number (7066250272474).
Almost surely, 214132500544947 is an apocalyptic number.
14132500544947 is a deficient number, since it is larger than the sum of its proper divisors (1).
14132500544947 is an equidigital number, since it uses as much as digits as its factorization.
14132500544947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2419200, while the sum is 49.
The spelling of 14132500544947 in words is "fourteen trillion, one hundred thirty-two billion, five hundred million, five hundred forty-four thousand, nine hundred forty-seven".
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