Base | Representation |
---|---|
bin | 1100110110100111110001… |
… | …1100011110101110111110 |
3 | 1212001001112022221221101011 |
4 | 3031221330130132232332 |
5 | 3323021410220311132 |
6 | 50020221134105434 |
7 | 2656020163011133 |
oct | 315517434365676 |
9 | 55031468857334 |
10 | 14132530244542 |
11 | 4559632985a06 |
12 | 1702b8b94b27a |
13 | 7b68cc0b72a8 |
14 | 36c0379bc58a |
15 | 197945e63b47 |
hex | cda7c71ebbe |
14132530244542 has 4 divisors (see below), whose sum is σ = 21198795366816. Its totient is φ = 7066265122270.
The previous prime is 14132530244501. The next prime is 14132530244621. The reversal of 14132530244542 is 24544203523141.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×141325302445422 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14132530244495 and 14132530244504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3533132561134 + ... + 3533132561137.
It is an arithmetic number, because the mean of its divisors is an integer number (5299698841704).
Almost surely, 214132530244542 is an apocalyptic number.
14132530244542 is a deficient number, since it is larger than the sum of its proper divisors (7066265122274).
14132530244542 is an equidigital number, since it uses as much as digits as its factorization.
14132530244542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7066265122273.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 14132530244542 its reverse (24544203523141), we get a palindrome (38676733767683).
The spelling of 14132530244542 in words is "fourteen trillion, one hundred thirty-two billion, five hundred thirty million, two hundred forty-four thousand, five hundred forty-two".
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