Base | Representation |
---|---|
bin | 10100100100001111010… |
… | …011001011001111010101 |
3 | 12000002222101000210222102 |
4 | 110210033103023033111 |
5 | 141123420014103042 |
6 | 3001132251411445 |
7 | 204051625440134 |
oct | 24441723131725 |
9 | 5002871023872 |
10 | 1413300925397 |
11 | 4a5417589419 |
12 | 1a9aa7753b85 |
13 | a337343b92a |
14 | 4c592d0991b |
15 | 26b6ac04b32 |
hex | 1490f4cb3d5 |
1413300925397 has 4 divisors (see below), whose sum is σ = 1413305839500. Its totient is φ = 1413296011296.
The previous prime is 1413300925339. The next prime is 1413300925411. The reversal of 1413300925397 is 7935290033141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 84742703236 + 1328558222161 = 291106^2 + 1152631^2 .
It is a cyclic number.
It is not a de Polignac number, because 1413300925397 - 224 = 1413284148181 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1413300921397) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1996928 + ... + 2610425.
It is an arithmetic number, because the mean of its divisors is an integer number (353326459875).
Almost surely, 21413300925397 is an apocalyptic number.
It is an amenable number.
1413300925397 is a deficient number, since it is larger than the sum of its proper divisors (4914103).
1413300925397 is an equidigital number, since it uses as much as digits as its factorization.
1413300925397 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4914102.
The product of its (nonzero) digits is 612360, while the sum is 47.
The spelling of 1413300925397 in words is "one trillion, four hundred thirteen billion, three hundred million, nine hundred twenty-five thousand, three hundred ninety-seven".
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