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1413332304211 is a prime number
BaseRepresentation
bin10100100100010001001…
…010111000000101010011
312000010001120002000121201
4110210101022320011103
5141124001032213321
63001135332132031
7204052456240432
oct24442112700523
95003046060551
101413332304211
114a5433270823
121a9ab6167017
13a3379aa7389
144c597157119
1526b6d852291
hex149112b8153

1413332304211 has 2 divisors, whose sum is σ = 1413332304212. Its totient is φ = 1413332304210.

The previous prime is 1413332304173. The next prime is 1413332304253. The reversal of 1413332304211 is 1124032333141.

It is a weak prime.

It is an emirp because it is prime and its reverse (1124032333141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1413332304211 - 211 = 1413332302163 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1413332304211.

It is not a weakly prime, because it can be changed into another prime (1413335304211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706666152105 + 706666152106.

It is an arithmetic number, because the mean of its divisors is an integer number (706666152106).

Almost surely, 21413332304211 is an apocalyptic number.

1413332304211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413332304211 is an equidigital number, since it uses as much as digits as its factorization.

1413332304211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1413332304211 its reverse (1124032333141), we get a palindrome (2537364637352).

The spelling of 1413332304211 in words is "one trillion, four hundred thirteen billion, three hundred thirty-two million, three hundred four thousand, two hundred eleven".