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141340334002033 is a prime number
BaseRepresentation
bin100000001000110001011100…
…011001101000111101110001
3200112110000002220010120222111
4200020301130121220331301
5122011210001001031113
61220334504132205321
741525334144235225
oct4010613431507561
9615400086116874
10141340334002033
114104310a89a111
1213a28853a69841
1360b344ab3191a
1426c8ca1548785
1511518be3c213d
hex808c5c668f71

141340334002033 has 2 divisors, whose sum is σ = 141340334002034. Its totient is φ = 141340334002032.

The previous prime is 141340334002027. The next prime is 141340334002061. The reversal of 141340334002033 is 330200433043141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123828645020224 + 17511688981809 = 11127832^2 + 4184697^2 .

It is a cyclic number.

It is not a de Polignac number, because 141340334002033 - 233 = 141331744067441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141340334001986 and 141340334002004.

It is not a weakly prime, because it can be changed into another prime (141340334002003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70670167001016 + 70670167001017.

It is an arithmetic number, because the mean of its divisors is an integer number (70670167001017).

Almost surely, 2141340334002033 is an apocalyptic number.

It is an amenable number.

141340334002033 is a deficient number, since it is larger than the sum of its proper divisors (1).

141340334002033 is an equidigital number, since it uses as much as digits as its factorization.

141340334002033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 141340334002033 its reverse (330200433043141), we get a palindrome (471540767045174).

The spelling of 141340334002033 in words is "one hundred forty-one trillion, three hundred forty billion, three hundred thirty-four million, two thousand, thirty-three".