Base | Representation |
---|---|
bin | 11010010100111010… |
… | …00101110010000011 |
3 | 1100111000200201021002 |
4 | 31022131011302003 |
5 | 212421303313411 |
6 | 10254301322215 |
7 | 1010153241515 |
oct | 151235056203 |
9 | 40430621232 |
10 | 14134041731 |
11 | 5aa3330827 |
12 | 28a556636b |
13 | 1443311204 |
14 | 981209bb5 |
15 | 57acae33b |
hex | 34a745c83 |
14134041731 has 2 divisors, whose sum is σ = 14134041732. Its totient is φ = 14134041730.
The previous prime is 14134041611. The next prime is 14134041793. The reversal of 14134041731 is 13714043141.
It is a strong prime.
It is an emirp because it is prime and its reverse (13714043141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14134041731 is a prime.
It is a super-2 number, since 2×141340417312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14134041694 and 14134041703.
It is not a weakly prime, because it can be changed into another prime (14134041331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7067020865 + 7067020866.
It is an arithmetic number, because the mean of its divisors is an integer number (7067020866).
Almost surely, 214134041731 is an apocalyptic number.
14134041731 is a deficient number, since it is larger than the sum of its proper divisors (1).
14134041731 is an equidigital number, since it uses as much as digits as its factorization.
14134041731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 14134041731 its reverse (13714043141), we get a palindrome (27848084872).
The spelling of 14134041731 in words is "fourteen billion, one hundred thirty-four million, forty-one thousand, seven hundred thirty-one".
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