14134044403 has 4 divisors (see below), whose sum is σ = 14434768800. Its totient is φ = 13833320008.

The previous prime is 14134044391. The next prime is 14134044481. The reversal of 14134044403 is 30444043141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30444043141 = 137 ⋅222219293.

It is a cyclic number.

It is not a de Polignac number, because 14134044403 - 2³³ = 5544109811 is a prime.

It is a super-2 number, since 2×14134044403² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14134044493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150362128 + ... + 150362221.

It is an arithmetic number, because the mean of its divisors is an integer number (3608692200).

Almost surely, 2^14134044403 is an apocalyptic number.

14134044403 is a deficient number, since it is larger than the sum of its proper divisors (300724397).

14134044403 is an equidigital number, since it uses as much as digits as its factorization.

14134044403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 300724396.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 14134044403 its reverse (30444043141), we get a palindrome (44578087544).

The spelling of 14134044403 in words is "fourteen billion, one hundred thirty-four million, forty-four thousand, four hundred three".