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1413414131 is a prime number
BaseRepresentation
bin101010000111110…
…1111110011110011
310122111120212200112
41110033233303303
510343313223011
6352130211535
750011551623
oct12417576363
93574525615
101413414131
11665920a58
12335423bab
13196a9732c
14d5a04883
158414458b
hex543efcf3

1413414131 has 2 divisors, whose sum is σ = 1413414132. Its totient is φ = 1413414130.

The previous prime is 1413414113. The next prime is 1413414137. The reversal of 1413414131 is 1314143141.

Together with previous prime (1413414113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (1314143141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1413414131 - 222 = 1409219827 is a prime.

It is a super-2 number, since 2×14134141312 = 3995479011420970322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1413414097 and 1413414106.

It is not a weakly prime, because it can be changed into another prime (1413414137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706707065 + 706707066.

It is an arithmetic number, because the mean of its divisors is an integer number (706707066).

Almost surely, 21413414131 is an apocalyptic number.

1413414131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413414131 is an equidigital number, since it uses as much as digits as its factorization.

1413414131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 23.

The square root of 1413414131 is about 37595.4003968571. The cubic root of 1413414131 is about 1122.2505054100.

Adding to 1413414131 its reverse (1314143141), we get a palindrome (2727557272).

The spelling of 1413414131 in words is "one billion, four hundred thirteen million, four hundred fourteen thousand, one hundred thirty-one".