Base | Representation |
---|---|
bin | 1100110110101110000111… |
… | …0100100011000010100101 |
3 | 1212001012220212022221012202 |
4 | 3031223201310203002211 |
5 | 3323033401122134303 |
6 | 50021102012224245 |
7 | 2656110264436601 |
oct | 315534164430245 |
9 | 55035825287182 |
10 | 14134231052453 |
11 | 455a325a50086 |
12 | 170338546b085 |
13 | 7b6b105874c5 |
14 | 36c159834501 |
15 | 1979e5426c88 |
hex | cdae1d230a5 |
14134231052453 has 16 divisors (see below), whose sum is σ = 14340921872256. Its totient is φ = 13928422072320.
The previous prime is 14134231052437. The next prime is 14134231052489. The reversal of 14134231052453 is 35425013243141.
It is a cyclic number.
It is not a de Polignac number, because 14134231052453 - 24 = 14134231052437 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14134231052423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160998776 + ... + 161086542.
It is an arithmetic number, because the mean of its divisors is an integer number (896307617016).
Almost surely, 214134231052453 is an apocalyptic number.
It is an amenable number.
14134231052453 is a deficient number, since it is larger than the sum of its proper divisors (206690819803).
14134231052453 is an equidigital number, since it uses as much as digits as its factorization.
14134231052453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 92764.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 14134231052453 its reverse (35425013243141), we get a palindrome (49559244295594).
The spelling of 14134231052453 in words is "fourteen trillion, one hundred thirty-four billion, two hundred thirty-one million, fifty-two thousand, four hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •