1413442043431 has 4 divisors (see below), whose sum is σ = 1541936774664. Its totient is φ = 1284947312200.

The previous prime is 1413442043413. The next prime is 1413442043483. The reversal of 1413442043431 is 1343402443141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413442043431 - 2¹¹ = 1413442041383 is a prime.

It is a super-2 number, since 2×1413442043431² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413442043491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64247365600 + ... + 64247365621.

It is an arithmetic number, because the mean of its divisors is an integer number (385484193666).

Almost surely, 2^{1413442043431} is an apocalyptic number.

1413442043431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1413442043431 is a deficient number, since it is larger than the sum of its proper divisors (128494731233).

1413442043431 is a wasteful number, since it uses less digits than its factorization.

1413442043431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128494731232.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 1413442043431 its reverse (1343402443141), we get a palindrome (2756844486572).

The spelling of 1413442043431 in words is "one trillion, four hundred thirteen billion, four hundred forty-two million, forty-three thousand, four hundred thirty-one".