Base | Representation |
---|---|
bin | 110101111010… |
… | …110010100001 |
3 | 222121002210112 |
4 | 311322302201 |
5 | 12104300213 |
6 | 1222541105 |
7 | 231066155 |
oct | 65726241 |
9 | 28532715 |
10 | 14134433 |
11 | 7a84455 |
12 | 4897795 |
13 | 2c0b691 |
14 | 1c3d065 |
15 | 1392ea8 |
hex | d7aca1 |
14134433 has 2 divisors, whose sum is σ = 14134434. Its totient is φ = 14134432.
The previous prime is 14134403. The next prime is 14134447. The reversal of 14134433 is 33443141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9690769 + 4443664 = 3113^2 + 2108^2 .
It is a cyclic number.
It is not a de Polignac number, because 14134433 - 26 = 14134369 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14134399 and 14134408.
It is not a weakly prime, because it can be changed into another prime (14134403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7067216 + 7067217.
It is an arithmetic number, because the mean of its divisors is an integer number (7067217).
Almost surely, 214134433 is an apocalyptic number.
It is an amenable number.
14134433 is a deficient number, since it is larger than the sum of its proper divisors (1).
14134433 is an equidigital number, since it uses as much as digits as its factorization.
14134433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 23.
The square root of 14134433 is about 3759.5788327950. The cubic root of 14134433 is about 241.7832052011.
Adding to 14134433 its reverse (33443141), we get a palindrome (47577574).
The spelling of 14134433 in words is "fourteen million, one hundred thirty-four thousand, four hundred thirty-three".
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