Base | Representation |
---|---|
bin | 1000001110100011010… |
… | …1101101000000000110 |
3 | 111111211121012111212212 |
4 | 2003220311231000012 |
5 | 4303433402024132 |
6 | 144533321143422 |
7 | 13132445420342 |
oct | 2035065550006 |
9 | 444747174785 |
10 | 141345345542 |
11 | 54a42843165 |
12 | 2348832ab72 |
13 | 1043751594b |
14 | 6bac194622 |
15 | 3a23dbc5b2 |
hex | 20e8d6d006 |
141345345542 has 4 divisors (see below), whose sum is σ = 212018018316. Its totient is φ = 70672672770.
The previous prime is 141345345523. The next prime is 141345345551. The reversal of 141345345542 is 245543543141.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 141345345542.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35336336384 + ... + 35336336387.
It is an arithmetic number, because the mean of its divisors is an integer number (53004504579).
Almost surely, 2141345345542 is an apocalyptic number.
141345345542 is a deficient number, since it is larger than the sum of its proper divisors (70672672774).
141345345542 is an equidigital number, since it uses as much as digits as its factorization.
141345345542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70672672773.
The product of its digits is 576000, while the sum is 41.
Adding to 141345345542 its reverse (245543543141), we get a palindrome (386888888683).
The spelling of 141345345542 in words is "one hundred forty-one billion, three hundred forty-five million, three hundred forty-five thousand, five hundred forty-two".
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