Base | Representation |
---|---|
bin | 10100100100011011111… |
… | …000000111111101011001 |
3 | 12000010112002002100200121 |
4 | 110210123320013331121 |
5 | 141124333024003011 |
6 | 3001205230233241 |
7 | 204060100141651 |
oct | 24443370077531 |
9 | 5003462070617 |
10 | 1413511937881 |
11 | 4a55157031aa |
12 | 1a9b46355821 |
13 | a33a80805a4 |
14 | 4c5b2d57361 |
15 | 26b7e4d6e71 |
hex | 1491be07f59 |
1413511937881 has 2 divisors, whose sum is σ = 1413511937882. Its totient is φ = 1413511937880.
The previous prime is 1413511937837. The next prime is 1413511937899. The reversal of 1413511937881 is 1887391153141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1402071496281 + 11440441600 = 1184091^2 + 106960^2 .
It is a cyclic number.
It is not a de Polignac number, because 1413511937881 - 217 = 1413511806809 is a prime.
It is a super-2 number, since 2×14135119378812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1413511977881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706755968940 + 706755968941.
It is an arithmetic number, because the mean of its divisors is an integer number (706755968941).
Almost surely, 21413511937881 is an apocalyptic number.
It is an amenable number.
1413511937881 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413511937881 is an equidigital number, since it uses as much as digits as its factorization.
1413511937881 is an evil number, because the sum of its binary digits is even.
The product of its digits is 725760, while the sum is 52.
The spelling of 1413511937881 in words is "one trillion, four hundred thirteen billion, five hundred eleven million, nine hundred thirty-seven thousand, eight hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •