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141352235121043 is a prime number
BaseRepresentation
bin100000001000111100100001…
…110000110011100110010011
3200112111010211022012002010001
4200020330201300303212103
5122011403334142333133
61220344153110350431
741526235105130212
oct4010744160634623
9615433738162101
10141352235121043
1141048167753a61
1213a2b01565b417
1360b45c665508b
1426c96add87079
151151d6910e87d
hex808f21c33993

141352235121043 has 2 divisors, whose sum is σ = 141352235121044. Its totient is φ = 141352235121042.

The previous prime is 141352235120977. The next prime is 141352235121067. The reversal of 141352235121043 is 340121532253141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141352235121043 is a prime.

It is a super-2 number, since 2×1413522351210432 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141352235120993 and 141352235121011.

It is not a weakly prime, because it can be changed into another prime (141352235121073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70676117560521 + 70676117560522.

It is an arithmetic number, because the mean of its divisors is an integer number (70676117560522).

Almost surely, 2141352235121043 is an apocalyptic number.

141352235121043 is a deficient number, since it is larger than the sum of its proper divisors (1).

141352235121043 is an equidigital number, since it uses as much as digits as its factorization.

141352235121043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 141352235121043 its reverse (340121532253141), we get a palindrome (481473767374184).

The spelling of 141352235121043 in words is "one hundred forty-one trillion, three hundred fifty-two billion, two hundred thirty-five million, one hundred twenty-one thousand, forty-three".