141353322511133 has 4 divisors (see below), whose sum is σ = 141804930570588. Its totient is φ = 140901714451680.

The previous prime is 141353322511109. The next prime is 141353322511157. The reversal of 141353322511133 is 331115223353141.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (141353322511109) and next prime (141353322511157).

It can be written as a sum of positive squares in 2 ways, for example, as 1979879754724 + 139373442756409 = 1407082^2 + 11805653^2 .

It is a cyclic number.

It is not a de Polignac number, because 141353322511133 - 2⁸ = 141353322510877 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141353322511733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225804029258 + ... + 225804029883.

It is an arithmetic number, because the mean of its divisors is an integer number (35451232642647).

Almost surely, 2^{141353322511133} is an apocalyptic number.

It is an amenable number.

141353322511133 is a deficient number, since it is larger than the sum of its proper divisors (451608059455).

141353322511133 is an equidigital number, since it uses as much as digits as its factorization.

141353322511133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 451608059454.

The product of its digits is 97200, while the sum is 38.

Adding to 141353322511133 its reverse (331115223353141), we get a palindrome (472468545864274).

The spelling of 141353322511133 in words is "one hundred forty-one trillion, three hundred fifty-three billion, three hundred twenty-two million, five hundred eleven thousand, one hundred thirty-three".