141354534321131 has 2 divisors, whose sum is σ = 141354534321132. Its totient is φ = 141354534321130.

The previous prime is 141354534321097. The next prime is 141354534321151. The reversal of 141354534321131 is 131123435453141.

It is a strong prime.

It is an emirp because it is prime and its reverse (131123435453141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141354534321131 - 2⁴⁶ = 70985790143467 is a prime.

It is a super-3 number, since 3×141354534321131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (141354534321151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70677267160565 + 70677267160566.

It is an arithmetic number, because the mean of its divisors is an integer number (70677267160566).

Almost surely, 2^{141354534321131} is an apocalyptic number.

141354534321131 is a deficient number, since it is larger than the sum of its proper divisors (1).

141354534321131 is an equidigital number, since it uses as much as digits as its factorization.

141354534321131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 259200, while the sum is 41.

Adding to 141354534321131 its reverse (131123435453141), we get a palindrome (272477969774272).

The spelling of 141354534321131 in words is "one hundred forty-one trillion, three hundred fifty-four billion, five hundred thirty-four million, three hundred twenty-one thousand, one hundred thirty-one".