Base | Representation |
---|---|
bin | 100000001001101001010101… |
… | …000110111011110101110011 |
3 | 200112122201222220021002211002 |
4 | 200021221111012323311303 |
5 | 122013200344321401433 |
6 | 1220422230414512215 |
7 | 41532560162063036 |
oct | 4011512506736563 |
9 | 615581886232732 |
10 | 141400341200243 |
11 | 41066603343304 |
12 | 13a3840020566b |
13 | 60b8cc1c0c2b8 |
14 | 26cbb54d5301d |
15 | 11532325979e8 |
hex | 809a551bbd73 |
141400341200243 has 2 divisors, whose sum is σ = 141400341200244. Its totient is φ = 141400341200242.
The previous prime is 141400341200161. The next prime is 141400341200257. The reversal of 141400341200243 is 342002143004141.
141400341200243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141400341200243 - 244 = 123808155155827 is a prime.
It is not a weakly prime, because it can be changed into another prime (141400341200263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70700170600121 + 70700170600122.
It is an arithmetic number, because the mean of its divisors is an integer number (70700170600122).
Almost surely, 2141400341200243 is an apocalyptic number.
141400341200243 is a deficient number, since it is larger than the sum of its proper divisors (1).
141400341200243 is an equidigital number, since it uses as much as digits as its factorization.
141400341200243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 141400341200243 its reverse (342002143004141), we get a palindrome (483402484204384).
The spelling of 141400341200243 in words is "one hundred forty-one trillion, four hundred billion, three hundred forty-one million, two hundred thousand, two hundred forty-three".
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