Base | Representation |
---|---|
bin | 10100100100111001110… |
… | …110011001010110100001 |
3 | 12000011211010022110122011 |
4 | 110210321312121112201 |
5 | 141131400242120223 |
6 | 3001331152312521 |
7 | 204105414333052 |
oct | 24447166312641 |
9 | 5004733273564 |
10 | 1414014801313 |
11 | 4a5753545a14 |
12 | 1aa066842741 |
13 | a34582c8b0a |
14 | 4c61da56729 |
15 | 26bad71880d |
hex | 14939d995a1 |
1414014801313 has 2 divisors, whose sum is σ = 1414014801314. Its totient is φ = 1414014801312.
The previous prime is 1414014801289. The next prime is 1414014801347. The reversal of 1414014801313 is 3131084104141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1131483218944 + 282531582369 = 1063712^2 + 531537^2 .
It is a cyclic number.
It is not a de Polignac number, because 1414014801313 - 221 = 1414012704161 is a prime.
It is not a weakly prime, because it can be changed into another prime (1414014801713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707007400656 + 707007400657.
It is an arithmetic number, because the mean of its divisors is an integer number (707007400657).
Almost surely, 21414014801313 is an apocalyptic number.
It is an amenable number.
1414014801313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414014801313 is an equidigital number, since it uses as much as digits as its factorization.
1414014801313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 1414014801313 its reverse (3131084104141), we get a palindrome (4545098905454).
The spelling of 1414014801313 in words is "one trillion, four hundred fourteen billion, fourteen million, eight hundred one thousand, three hundred thirteen".
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