Base | Representation |
---|---|
bin | 10100100100111011000… |
… | …000001000010110000011 |
3 | 12000011212110200111000211 |
4 | 110210323000020112003 |
5 | 141131420214132212 |
6 | 3001333122454551 |
7 | 204106040535601 |
oct | 24447300102603 |
9 | 5004773614024 |
10 | 1414034130307 |
11 | 4a5763448097 |
12 | 1aa071204457 |
13 | a345c3059a6 |
14 | 4c622448871 |
15 | 26bb02859a7 |
hex | 1493b008583 |
1414034130307 has 2 divisors, whose sum is σ = 1414034130308. Its totient is φ = 1414034130306.
The previous prime is 1414034130287. The next prime is 1414034130323. The reversal of 1414034130307 is 7030314304141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1414034130307 is a prime.
It is a super-3 number, since 3×14140341303073 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1414034130347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707017065153 + 707017065154.
It is an arithmetic number, because the mean of its divisors is an integer number (707017065154).
Almost surely, 21414034130307 is an apocalyptic number.
1414034130307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414034130307 is an equidigital number, since it uses as much as digits as its factorization.
1414034130307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 1414034130307 its reverse (7030314304141), we get a palindrome (8444348434448).
The spelling of 1414034130307 in words is "one trillion, four hundred fourteen billion, thirty-four million, one hundred thirty thousand, three hundred seven".
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