1414040241333 has 4 divisors (see below), whose sum is σ = 1885386988448. Its totient is φ = 942693494220.

The previous prime is 1414040241331. The next prime is 1414040241389. The reversal of 1414040241333 is 3331420404141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1414040241333 - 2¹ = 1414040241331 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1414040241333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1414040241331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235673373553 + ... + 235673373558.

It is an arithmetic number, because the mean of its divisors is an integer number (471346747112).

Almost surely, 2^{1414040241333} is an apocalyptic number.

It is an amenable number.

1414040241333 is a deficient number, since it is larger than the sum of its proper divisors (471346747115).

1414040241333 is an equidigital number, since it uses as much as digits as its factorization.

1414040241333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471346747114.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 1414040241333 its reverse (3331420404141), we get a palindrome (4745460645474).

The spelling of 1414040241333 in words is "one trillion, four hundred fourteen billion, forty million, two hundred forty-one thousand, three hundred thirty-three".