141404412301 has 4 divisors (see below), whose sum is σ = 145226153212. Its totient is φ = 137582671392.

The previous prime is 141404412277. The next prime is 141404412323. The reversal of 141404412301 is 103214404141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 103214404141 = 124181 ⋅831161.

It can be written as a sum of positive squares in 2 ways, for example, as 72616236676 + 68788175625 = 269474^2 + 262275^2 .

It is a cyclic number.

It is not a de Polignac number, because 141404412301 - 2¹¹ = 141404410253 is a prime.

It is a super-2 number, since 2×141404412301² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141404412361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1910870400 + ... + 1910870473.

It is an arithmetic number, because the mean of its divisors is an integer number (36306538303).

Almost surely, 2^141404412301 is an apocalyptic number.

It is an amenable number.

141404412301 is a deficient number, since it is larger than the sum of its proper divisors (3821740911).

141404412301 is an equidigital number, since it uses as much as digits as its factorization.

141404412301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3821740910.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 141404412301 its reverse (103214404141), we get a palindrome (244618816442).

The spelling of 141404412301 in words is "one hundred forty-one billion, four hundred four million, four hundred twelve thousand, three hundred one".