Base | Representation |
---|---|
bin | 10100100100111111100… |
… | …010100100000000000111 |
3 | 12000012001202221112200021 |
4 | 110210333202210000013 |
5 | 141132044211442401 |
6 | 3001344442400011 |
7 | 204110653633630 |
oct | 24447742440007 |
9 | 5005052845607 |
10 | 1414110265351 |
11 | 4a57a2419513 |
12 | 1aa092800007 |
13 | a3472011b04 |
14 | 4c62c5c6887 |
15 | 26bb6cc42a1 |
hex | 1493f8a4007 |
1414110265351 has 4 divisors (see below), whose sum is σ = 1616126017552. Its totient is φ = 1212094513152.
The previous prime is 1414110265319. The next prime is 1414110265369. The reversal of 1414110265351 is 1535620114141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1414110265351 - 25 = 1414110265319 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1414110245351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101007876090 + ... + 101007876103.
It is an arithmetic number, because the mean of its divisors is an integer number (404031504388).
Almost surely, 21414110265351 is an apocalyptic number.
1414110265351 is a deficient number, since it is larger than the sum of its proper divisors (202015752201).
1414110265351 is an equidigital number, since it uses as much as digits as its factorization.
1414110265351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 202015752200.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 1414110265351 its reverse (1535620114141), we get a palindrome (2949730379492).
The spelling of 1414110265351 in words is "one trillion, four hundred fourteen billion, one hundred ten million, two hundred sixty-five thousand, three hundred fifty-one".
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