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141412433 is a prime number
BaseRepresentation
bin10000110110111…
…00100001010001
3100212002111101112
420123130201101
5242200144213
622010543105
73334662101
oct1033344121
9325074345
10141412433
1172907288
123b437a95
13233b31c6
1414ad1201
15c634ea8
hex86dc851

141412433 has 2 divisors, whose sum is σ = 141412434. Its totient is φ = 141412432.

The previous prime is 141412417. The next prime is 141412463. The reversal of 141412433 is 334214141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138956944 + 2455489 = 11788^2 + 1567^2 .

It is a cyclic number.

It is not a de Polignac number, because 141412433 - 24 = 141412417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141412399 and 141412408.

It is not a weakly prime, because it can be changed into another prime (141412463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70706216 + 70706217.

It is an arithmetic number, because the mean of its divisors is an integer number (70706217).

Almost surely, 2141412433 is an apocalyptic number.

It is an amenable number.

141412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

141412433 is an equidigital number, since it uses as much as digits as its factorization.

141412433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 23.

The square root of 141412433 is about 11891.6959681956. The cubic root of 141412433 is about 520.9897728991.

Adding to 141412433 its reverse (334214141), we get a palindrome (475626574).

The spelling of 141412433 in words is "one hundred forty-one million, four hundred twelve thousand, four hundred thirty-three".