141412434301442 has 4 divisors (see below), whose sum is σ = 212118651452166. Its totient is φ = 70706217150720.

The previous prime is 141412434301429. The next prime is 141412434301459. The reversal of 141412434301442 is 244103434214141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 117167830199281 + 24244604102161 = 10824409^2 + 4923881^2 .

It is a junction number, because it is equal to n+sod(n) for n = 141412434301396 and 141412434301405.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35353108575359 + ... + 35353108575362.

Almost surely, 2^{141412434301442} is an apocalyptic number.

141412434301442 is a deficient number, since it is larger than the sum of its proper divisors (70706217150724).

141412434301442 is an equidigital number, since it uses as much as digits as its factorization.

141412434301442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70706217150723.

The product of its (nonzero) digits is 147456, while the sum is 38.

Adding to 141412434301442 its reverse (244103434214141), we get a palindrome (385515868515583).

The spelling of 141412434301442 in words is "one hundred forty-one trillion, four hundred twelve billion, four hundred thirty-four million, three hundred one thousand, four hundred forty-two".